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今天遇到一个问题，需要查看一个函数是定义在哪个模块的， 从而去定位这个模块，翻看其源码。因为我们的环境还不容许使用Reflection APIS, 就直接写脚本了, 没什么大用，就是挺有意思的，；）
get_function_container.php
<?php
$function_name = $argv[1];
$modules = get_loaded_extensions();
foreach($modules as $m){
$funcs = get_extension_funcs($m);
if(in_array($function_name, $funcs)){
printf("%s was defined in Module: %s\n", $function_name, $m);;
exit;
}
}
print $function_name ." Must be defined in user defined PHP script files\n";
?>
使用方法:
php -f get_function_container.php 'function_name'
有点意思~~
非常感谢您的分享
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仅能够找函数，结构语言就找不到，比如echo
$funcs = get_extension_funcs($m);
此句会出现非数组的警告，应该改为：
$funcs = (array)get_extension_funcs($m);
php手册:
Description
array get_loaded_extensions ( void )
,,,,因为我们的环境还不容许使用Reflection APIS, 就直接写脚本了, 没什么大用，就是挺有意思的，；）
C:\>php －－rf array_search
Function [ ＜internal:standard＞ function array_search ] {
– Parameters [3] {
Parameter #0 [ $needle ]
Parameter #1 [ $haystack ]
Parameter #2 [ $strict ]
}
}
哦？ 受教了，谢谢，呵呵。
发现这段代码貌似有点问题:因为不是每个module用get_extension_funcs返回的都是数组,所以可以改动代码如下:
<?php
$function_name = $argv[1];
$modules = get_loaded_extensions();
foreach($modules as $m){
$funcs = get_extension_funcs($m);
if (is_array($funcs)){
if(in_array($function_name, $funcs)){
printf(“%s was defined in Module: %s\n”, $function_name, $m);;
exit;
}
}
}